-x^2+200x-3600=0

Solution for -x^2+200x-3600=0 equation:

-x^2+200x-3600=0

We add all the numbers together, and all the variables

-1x^2+200x-3600=0

a = -1; b = 200; c = -3600;
Δ = b2-4ac
Δ = 2002-4·(-1)·(-3600)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-160}{2*-1}=\frac{-360}{-2}
=+180
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+160}{2*-1}=\frac{-40}{-2}
=+20
$